c=116(295^2/3)+1269

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Solution for c=116(295^2/3)+1269 equation: 



c=116(295^2/3)+1269

We move all terms to the left:

c-(116(295^2/3)+1269)=0

We multiply all the terms by the denominator


c*3)+1269)-(116(295^2=0

Wy multiply elements

3c^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{6}=0$

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